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\pi_C(t+1)=\sum_{C'} \pi_{C'}(t) p_{C' \to C}

Questions and Remarks:

  • Q: in the first variant we should replace a=choice(L) - actually there are two line which read "a = choice(L)": one two choose a random disc to propose a move, and one to calculate the pair correlation. Which lines should be replaced? the first, the second or both? - maximilian.trescher maximilian.trescher
  • A: you have to replace both instances. - vivien.lecomte vivien.lecomte

  • Q: in the question about the two variants of the MC algorithm, the second variant includes both the replacements or only the second one? - tommaso.comparin tommaso.comparin
  • A: the second variant include only the replacement for b. - vivien.lecomte vivien.lecomte

  • Q: In the question 2 of the very first section ("why can we forget about the velocities?"), I'm not sure what the question is about: should we disscuss the fact that we are sampling equilibrium, distribution or compare the algorithms to molecular dynamics? - felix.rose felix.rose
  • A: The dynamics of hard spheres is described by their individual uniform motion punctuated by collisions. It occurs in phase space, whose coordinates consists of the set of their positions and velocities. As discussed in the lectures and in the class sessions, according to the ergodic hypothesis, their stationnary distribution is uniform in phase space (which includes positions and velocities). However, in the proposed programs, the sampling is performed uniquely on positions. We ask to justify why we can forget about the velocities. - vivien.lecomte vivien.lecomte

  • Q: In the questions about the algorithm A, what is exactly the property ? I read it as "the probability to find a disk at position (x,y) is uniform in space" but this is clearly false (as the histogram of the x-coordinate of the disks shows), so I do not understand the following questions. - felix.rose felix.rose
  • A: The hard spheres are distributed with the microcanonical distribution: their probability density in phase space is uniform. The property that we ask you to decide whether it is true of false indeed reads: "the probability to find the center of a disk at spatial position (x,y) is uniform". In question 2, you have to justify theoretically why you think this property is true or false. In the following questions (3 and 4), you have to test your choice numerically.
    Besides, we cannot comment on the rest of your remark « but this is clearly false (as the histogram of the x-coordinate of the disks shows) », as it would partially answer to the question. However, we advice you to clearly identify and rethink of the premises and implications of your reasoning. - vivien.lecomte vivien.lecomte

  • Q: I think %1 is missing in the last question (second variant). - Riccardo.Rossi Riccardo.Rossi
  • A: Yes. The question is now reformulated in a clearer way. - vivien.lecomte vivien.lecomte